Wednesday, July 17, 2019

Date and Observations Essay

1. Write the fit equation for the reaction conducted in this lab, including appropriate physique symbols.Mg(s) + 2HCl(aq) H2(g) + MgCl2(aq) 2. chink the overtone pressure of the hydrogen accelerator pedal collected in the shooter ingathering pipework. The partial pressure of the hydrogen artillery is 1.07 atm 3. compute the moles of hydrogen throttle collected.pv=mrt n= .0013mol of hydrogen gas 4. If magnesium was the limiting reactant in this lab, calculate the divinatory production of the gaseous product. Show all move of your calculation.0.03184 g Mg(1mol Mg/ 24.3050 g Mg)= 0.0013mols Mg0.0013mols Mg(1mol H2/ 1mol Mg)= .00131. Determine the part yield of this reaction, showing all go of your calculation.2. (actual yield/ theoretical yield)x cytosine%(0.0013/ 0.0013)x 100= 100%1. Would the fol woefuling errors increase, decrease, or have no event on the measured moles of gas collected in the experiment? rationalize your answers in complete sentences. a. The mensural mass of the magnesium was smaller than the true mass. If the heedful add together of magnesium is less than the true amount of magnesium then the measured issue of moles would be trim down than the measured number of hydrogen would be smaller than the true number of moles of hydrogen. It would decrease the calculated moles of the gas. b. The actual temperature of the hydrogen gas is trim back than fashion temperature. If the actual temperature of hydrogen gas is lower than path temperature then the actual amount of hydrogen gas would be high than the gas at means temperature. So therefore it would increase the number of moles produce.2. Explain in terms of particle collisions and Daltons rightfulness why it can be assumed that the positive pressure inside the gas collection pipe is equal to the atmospheric pressure after-school(prenominal) of the tube. If the number of particle collisions and the pressure inside the gas collection tube was high it would force t he water in the gas collection tube to be lower than the surrounding water. If the number of particle collisions and the pressure was low the surrounding water would push the water higher into the gas collection tube. When the water is even, inside and outside of the tube, the number ofparticle collisions and the pressure are equal.3. If an unobserved air erupt was trapped inside the gas collection tube, how would this affect your calculated percent yield? Explain your answer.4. If there was an undetected air bubble trapped in the gas collection tube then the pressure of hydrogen would be lower then the actual value therefore the percent yield would be lower than the actual percent yield.

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.